[tex]2 imes \frac{5}{3} + \frac{12}{6} [/tex]3! × 2! - 0! + 1!

Question

[tex]2 	imes \frac{5}{3}  +  \frac{12}{6} [/tex]3! × 2! - 0! + 1!​

illmiii · Accepted Answer

[tex]\bf  2 	imes  \frac{5}{3}  +  \frac{12}{6}  =   \frac{2}{1}  	imes  \frac{5}{3}  +  \frac{12}{6}  =  \frac{10}{3}  +  \frac{12}{6}  \\bf    =  \frac{20 + 12}{6}  =  \frac{32}{6}  =  \frac{16}{6}  =  \frac{8}{3}  = 1 \frac{5}{3} [/tex]3! × 2! - 0! + 1!= (3.2.1) × (2.1) - 0 + 1= 6 × 2 - 0 + 1= 12

egaagulia · Answer

2 x 5/3 + 12/6= (2/1 x 5/3) + 12/6= 10/3 + 12/6= 20/6 + 12/6= 32/6= 5 2/6= 5 1/33! × 2! - 0! + 1!= (3.2.1) × (2.1) - 0 + 1= (6 × 2) - 0 + 1= 12 - 0 + 1= 12 + 1= 13

$2 \times \frac{5}{3} + \frac{12}{6}$

3! × 2! - 0! + 1!

Pertanyaan baru di Matematika

Unduh Brainly Gratis!

3! × 2! - 0! + 1!​

Pertanyaan baru di Matematika

$2 \times \frac{5}{3} + \frac{12}{6}$

3! × 2! - 0! + 1!