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MaulanaAlief · Answer

[tex]\frac{2 \sqrt{2} + \sqrt{3}}{2 \sqrt{2} - \sqrt{3}} = \frac{2 \sqrt{2} + \sqrt{3}}{2 \sqrt{2} - \sqrt{3}} 	imes \frac{2 \sqrt{2} + \sqrt{3}}{2 \sqrt{2} + \sqrt{3}} [/tex][tex]= \frac{(2 \sqrt{2} + \sqrt{3})(2 \sqrt{2} + \sqrt{3})}{(2 \sqrt{2} - \sqrt{3})(2 \sqrt{2} + \sqrt{3})} [/tex][tex]= \frac{4 \sqrt{4} + 2 \sqrt{6} + 2 \sqrt{6} + \sqrt{9}}{4 \sqrt{4} + 2 \sqrt{6} - 2 \sqrt{6} - \sqrt{9}} [/tex][tex]= \frac{4 \sqrt{4} + 4 \sqrt{6} + \sqrt{9}}{4 \sqrt{4} - \sqrt{9}} [/tex][tex]= \frac{4 	imes 2 + 4 \sqrt{6} + 3}{4 	imes 2 - 3}[/tex][tex]= \frac{8 + 4 \sqrt{6} + 3}{8 - 3} = \frac{8 + 3 + 4 \sqrt{6}}{5} = \frac{11 + 4 \sqrt{6}}{5} [/tex]

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