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Jawaban:

2x-5y+3z =-10 ..... (1)

3x+4y+7z=-11 .....(2)

5x+3y+7z=-8 .........(3)

Eliminasi per (2) dan (1)

3x+4y+7z=-11 | ×2 | 6x+8y+14z=-22

2x-5y+3z =-10 | ×3 | 6x-15y+9z =-30

--------------------------- -

23y + 5z = 8 .....(4)

Eliminasi per (1) dan (3)

2x-5y+3z=-10 |×5| 10x-25y+15z=-50

5x+3y+7z=-8 |×2| 10x+6y+14z=-16

------------------------------- -

-31y + z =-34 ..... (5)

Eliminasi per (4) dan (5)

23y+5z=8 |×1| 23y+5z=8

-31y+z=-34 |×5| -155y+5z=-170

-------------------------- -

178y = 178

y= 1

subtitusi y ke per (4)

23y + 5z = 8

23(1)+5z=8

23+5z=8

5z= 8-23

5z= -15

z=-3

subtitusi y dan z ke per (1)

2x-5y+3z=-10

2x-5(1)+3(-3)=-10

2x-5-9=-10

2x=-10+5+9

2x= 4

x=2

hasil kali x,y,z

2×1×(-3) =-6

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